4x^2-50x+150=300

Solution for 4x^2-50x+150=300 equation:

4x^2-50x+150=300

We move all terms to the left:

4x^2-50x+150-(300)=0

We add all the numbers together, and all the variables

4x^2-50x-150=0

a = 4; b = -50; c = -150;
Δ = b2-4ac
Δ = -502-4·4·(-150)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-70}{2*4}=\frac{-20}{8}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+70}{2*4}=\frac{120}{8}
=15
$